$\displaystyle x^2 + y^2 = 9,$ $\displaystyle y = x^2 + 4$ I don't know, but do you just substitute in y and solve? Thanks for the help!^^
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Put x^2 = y - 4 in the first equation and solve the quadratics for y.
oops. my mistake. the equations were: $\displaystyle x^2 + y^2 = 9, $ $\displaystyle y = 2x -3 $
Square the second equation to get: (2x-3)^2. Substitute that into the first equation. Solve for x. Plug the value you found for x back into equation 2, that gives you y.
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