ok so my teacher gave me this problem: x+1/x^2-x-2 > 0 actually the inequality sign is "greater than or equal to" i just dont know how to type it in so how do i solve this you guys?
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Originally Posted by behindDkeys ok so my teacher gave me this problem: x+1/x^2-x-2 > 0 actually the inequality sign is "greater than or equal to" i just dont know how to type it in so how do i solve this you guys? Hi Do you mean $\displaystyle \frac{x+1}{x^2-x-2} \geq 0$ ? If so note that $\displaystyle x^2-x-2 = (x-2)(x+1)$
Originally Posted by running-gag Hi Do you mean $\displaystyle \frac{x+1}{x^2-x-2} \geq 0$ ? If so note that $\displaystyle x^2-x-2 = (x-2)(x+1)$ yes yes its that!!!! oh so i can factor it out i forgot about factoring hmmm then i can cancel out x+1 which leaves me with x-2 is greater than or equal to 0 right? whats next to that? coz i dont have y
Originally Posted by behindDkeys hmmm then i can cancel out x+1 which leaves me with x-2 is greater than or equal to 0 right? Yes but 2 is a forbidden value because makes the denominator equal to 0
Originally Posted by running-gag Yes but 2 is a forbidden value because makes the denominator equal to 0 so then i put it to the other side making it x>2?
Originally Posted by behindDkeys so then i put it to the other side making it x>2? Yes
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