as i return from vacation i forgot how to do this and i kinda lost my notes "Solve for the solution of:" $\displaystyle y=x^2, y=8-x^2 $ please show me step by step
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Originally Posted by behindDkeys as i return from vacation i forgot how to do this and i kinda lost my notes "Solve for the solution of:" $\displaystyle y=x^2, y=8-x^2 $ please show me step by step Set them equal and solve for x $\displaystyle x^2 = 8-x^2$ which cancels down to $\displaystyle x^2-4 = 0$ Solve using the difference of two squares
Originally Posted by e^(i*pi) Set them equal and solve for x $\displaystyle x^2 = 8-x^2$ which cancels down to $\displaystyle x^2-4 = 0$ Solve using the difference of two squares oh yea and im gonna have answer of -2 and positive 2 now i remember thanks
Last edited by behindDkeys; May 16th 2010 at 11:03 AM. Reason: wrong numbers XD
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