1. ## Lines

I need this F up in less then 3 weeks or I faile please help me!!!!!!!!!!!

view attchatment if this does no show clear.

THANK YOU!!!!!!!!!!!

Lesson 12 Assignment

[FONT='Arial','sans-serif'][/FONT]

[FONT='Arial','sans-serif']Identify the following:[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif']Equation of the blue line:[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif']Is the blue line part of the solution set? How do you know?[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif']Equation of the red line:[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif']Is the red line part of the solution set? How do you know?[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif']Are these points part of the solution?[/FONT]
[FONT='Arial','sans-serif'](0, 0)[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif'](4, 5)[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif'](3, -6)[/FONT]
[FONT='Arial','sans-serif'][/FONT]
[FONT='Arial','sans-serif'](-8, -2)[/FONT]

2. Originally Posted by jeilynn
I need this F up in less then 3 weeks or I faile please help me!!!!!!!!!!!

view attchatment if this does no show clear.

THANK YOU!!!!!!!!!!!

Lesson 12 Assignment

[FONT='Arial','sans-serif'][/font]

[FONT='Arial','sans-serif']Identify the following:[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif']Equation of the blue line:[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif']Is the blue line part of the solution set? How do you know?[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif']Equation of the red line:[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif']Is the red line part of the solution set? How do you know?[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif']Are these points part of the solution?[/font]
[FONT='Arial','sans-serif'](0, 0)[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif'](4, 5)[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif'](3, -6)[/font]
[FONT='Arial','sans-serif'][/font]
[FONT='Arial','sans-serif'](-8, -2)[/font]
the blue line passes through the points (0,5) and (4,3) i think, can't really see clearly, the lines are thick and the shading gets in the way. so the slope for the blue line is given by
m = (y2 - y1)/(x2 - x1) = (3 - 5)/(4 - 0) = -2/4 = -1/2

using m = -1/2 and (x1,y1) = (0,5), by the point slope form we have:

y - y1 = m(x - x1)
=> y - 5 = (-1/2)(x - 0)
=> y = (-1/2)x + 5 .....................equation of the blue line

yes, the blue line is a part of the solution set, since it is solid (unbroken)

the red line passes through the points (0,-1) and (-2,-2), so the slope for the red line is given by
m = (y2 - y1)/(x2 - x1) = (-2 + 1)/(-2 - 0) = -1/-2 = 1/2

using m = 1/2, and (x1,y1) = (0,-1), we have by the point-slope form:

y - y1 = m(x - x1)
=> y + 1 = (1/2)(x - 0)
=> y = (1/2)x - 1 .....................equation of the red line

no, the red line is not a part of the solution set, since it is broken

(0,0) yes, it's in the shaded region

(4,5) yes, it's in the shaded region

(3,-6) yes, it's in the shaded region

(-8,-2) yes, it's in the shaded region

hmmm...this makes me think that the solution they are looking for is where the shaded regions overlap, since they wouldn't make all the points in there. if that's the case:

(0,0) yes, it's in the shaded region

(4,5) no, it's in the overlapping shaded region

(3,-6) no, it's in the overlapping shaded region

(-8,-2) yes, it's in the shaded region