Results 1 to 2 of 2

Math Help - Lines

  1. #1
    Newbie
    Joined
    May 2007
    Posts
    10

    Lines

    I need this F up in less then 3 weeks or I faile please help me!!!!!!!!!!!

    view attchatment if this does no show clear.

    THANK YOU!!!!!!!!!!!



    Lesson 12 Assignment

    [FONT='Arial','sans-serif'][/FONT]

    [FONT='Arial','sans-serif']Identify the following:[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif']Equation of the blue line:[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif']Is the blue line part of the solution set? How do you know?[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif']Equation of the red line:[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif']Is the red line part of the solution set? How do you know?[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif']Are these points part of the solution?[/FONT]
    [FONT='Arial','sans-serif'](0, 0)[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif'](4, 5)[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif'](3, -6)[/FONT]
    [FONT='Arial','sans-serif'][/FONT]
    [FONT='Arial','sans-serif'](-8, -2)[/FONT]

    Attached Files Attached Files
    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by jeilynn View Post
    I need this F up in less then 3 weeks or I faile please help me!!!!!!!!!!!

    view attchatment if this does no show clear.

    THANK YOU!!!!!!!!!!!



    Lesson 12 Assignment

    [FONT='Arial','sans-serif'][/font]

    [FONT='Arial','sans-serif']Identify the following:[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif']Equation of the blue line:[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif']Is the blue line part of the solution set? How do you know?[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif']Equation of the red line:[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif']Is the red line part of the solution set? How do you know?[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif']Are these points part of the solution?[/font]
    [FONT='Arial','sans-serif'](0, 0)[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif'](4, 5)[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif'](3, -6)[/font]
    [FONT='Arial','sans-serif'][/font]
    [FONT='Arial','sans-serif'](-8, -2)[/font]
    the blue line passes through the points (0,5) and (4,3) i think, can't really see clearly, the lines are thick and the shading gets in the way. so the slope for the blue line is given by
    m = (y2 - y1)/(x2 - x1) = (3 - 5)/(4 - 0) = -2/4 = -1/2

    using m = -1/2 and (x1,y1) = (0,5), by the point slope form we have:

    y - y1 = m(x - x1)
    => y - 5 = (-1/2)(x - 0)
    => y = (-1/2)x + 5 .....................equation of the blue line


    yes, the blue line is a part of the solution set, since it is solid (unbroken)


    the red line passes through the points (0,-1) and (-2,-2), so the slope for the red line is given by
    m = (y2 - y1)/(x2 - x1) = (-2 + 1)/(-2 - 0) = -1/-2 = 1/2

    using m = 1/2, and (x1,y1) = (0,-1), we have by the point-slope form:

    y - y1 = m(x - x1)
    => y + 1 = (1/2)(x - 0)
    => y = (1/2)x - 1 .....................equation of the red line

    no, the red line is not a part of the solution set, since it is broken


    (0,0) yes, it's in the shaded region

    (4,5) yes, it's in the shaded region

    (3,-6) yes, it's in the shaded region

    (-8,-2) yes, it's in the shaded region

    hmmm...this makes me think that the solution they are looking for is where the shaded regions overlap, since they wouldn't make all the points in there. if that's the case:

    (0,0) yes, it's in the shaded region

    (4,5) no, it's in the overlapping shaded region

    (3,-6) no, it's in the overlapping shaded region

    (-8,-2) yes, it's in the shaded region
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Lines of best fit
    Posted in the Advanced Algebra Forum
    Replies: 1
    Last Post: September 24th 2011, 11:38 AM
  2. Replies: 1
    Last Post: April 17th 2010, 11:52 PM
  3. Replies: 1
    Last Post: March 14th 2010, 01:22 PM
  4. Replies: 2
    Last Post: January 25th 2009, 08:41 PM
  5. Lines
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: August 2nd 2007, 11:43 PM

Search Tags


/mathhelpforum @mathhelpforum