# What to do with this geometric problem

• May 13th 2010, 01:07 PM
florx
What to do with this geometric problem
http://i39.tinypic.com/whz11f.jpg

• May 13th 2010, 04:08 PM
ellensius
(a)

I guess there is a more pretty way to write this?

The algorithm below does what it says in the question. You put 500\$ a month, next time you put money it has passed a month, the account change, so you update the account with the compounded interest before you add the 500.
the time(t)=1/12, and r=0.03

...repeat for all the months.

formula:
f(t) = Pe^tr
Continuously Compounded Interest Formula and Calculator

algorithm:
Code:

```var months = 24; var rate = 0.03; var deposite = 500; var account = 500; i=1; while(i<months) {         account = account*(Math.pow(Math.E,((1/12)*rate)));         account +=deposite;         trace(account);         i++; }```
Code:

```1001.2515638028976 1503.7578242325983 2007.5219219548653 2512.5470054969496 3018.836231267267 3526.392763575127 4035.219774650508 4545.3204446638865 5056.69796174611 5569.355522008325 6083.296329561952 6598.523596538711 7115.040543110698 7632.85039751051 8151.956396051423 8672.361783147619 9194.069811334459 9717.083741288818 10241.40684184946 10767.042390037474 11293.993671076743 11822.263978414492 12351.85661374186```