# Thread: Help with Log Equation

1. ## Help with Log Equation

I am having trouble figuring the steps to solving the following. Can someone please show me so I can have a visual to better understand.
I am trying to solve for I.

1=6-5/2log(I/Io)

$\displaystyle 1=6-\frac{5}{2\log\frac{I}{I_0}}$

3. Sorry It is 5/2. thanks for the reply.

4. This one? $\displaystyle 1=6-\frac{5}{2}\log\frac{I}{I_0}$

5. Yes...that is the equation I am trying to solve. I'm not sure how to go about doing so.

6. $\displaystyle 1=6-\frac{5}{2}\log\frac{I}{I_0}$

$\displaystyle \frac{5}{2}\log\frac{I}{I_0} = 5$

$\displaystyle \log\frac{I}{I_0} = 2$

$\displaystyle \frac{I}{I_0} = 100$

finish it.

7. But skeeter, is this base $\displaystyle 10$ or base $\displaystyle e$ ?

8. Originally Posted by pickslides
But skeeter, is this base $\displaystyle 10$ or base $\displaystyle e$ ?
looks like a sound level equation ... decibels in base 10.

9. Skeeter,

Thanks a ton sir....I see that you're a Naval Aviator. I'm a flight deck AT myself out on recruiting duty. I'm pretty sure that it is a base 10. At least the textbook explanation of common logs has it a base 10.

10. It is the magnitude of a star model. I= the intensity of the star being measured.

11. Originally Posted by AlanL
Skeeter,

Thanks a ton sir....I see that you're a Naval Aviator.
retired ... haven't grabbed a yoke or pushed a rudder pedal since 1990.

... and yes, I do miss it.