Hello darkfenix21I'm not sure what you mean here. The vectors and are at for all positive values of .

Solve the quadratic equation:The second question is similar:

Find the value of "p" if the vectors r=(p,p,1) and s+(p,-2,-3) are perpendicular to each other

again i used the dot product and got

0=lal lbl cos90

0= (p)(p) +(p)(-2)+(-1)(3)

0= (p^2) -2p -3

3= (p^2) -2p

this is where I get stuck so if anyone could help me out it would be much appreciated thank you

You can do that, can't you?

Grandad