# Thread: Use the Binomial Theorem to find the 3rd term of (4x+3y)^9

1. ## Use the Binomial Theorem to find the 3rd term of (4x+3y)^9

My problem is that I'm going through a practice exam and my answer does not match any of the choices. Please help me to determine if my formula is incorrect. Thanks in advance!

Use the Binomial Theorem to find the 3rd term of (4x+3y)^9

3=2+1, thus k = 2, a = 4x, b = 3y, n = 9

9!/(2!7!)*4x^7*3y^2

a) 419,894x^7y^2; b) 314,928x^7y^2, c) 419,904x^2y^8, or d) 1,259,712x^2y^7

Please tell me what I'm doing wrong, I just don't get it...

2. Originally Posted by lilrhino
My problem is that I'm going through a practice exam and my answer does not match any of the choices. Please help me to determine if my formula is incorrect. Thanks in advance!

Use the Binomial Theorem to find the 3rd term of (4x+3y)^9

3=2+1, thus k = 2, a = 4x, b = 3y, n = 9

9!/(2!7!)*4x^7*3y^2

a) 419,894x^7y^2; b) 314,928x^7y^2, c) 419,904x^2y^8, or d) 1,259,712x^2y^7

Please tell me what I'm doing wrong, I just don't get it...
i actually got the same as you did

let me try something else

yes, you got the right answer, i don't know what happened, but either you or the book your looking out of made a typo somewhere. are you sure the signs are right place and everything?

3. Originally Posted by Jhevon
i actually got the same as you did

let me try something else

yes, you got the right answer, i don't know what happened, but either you or the book your looking out of made a typo somewhere. are you sure the signs are right and everything?
Jhevon, I double-checked and it says to find the 3rd term of (4x+3y)^9

Maybe it is a typo then...