Can somebody help me solve this equation? I have gotten to a certain point then get stuck. Thank you! 2/x^2-x = (1/x) + (4/x^2-1)
Last edited by mr fantastic; May 11th 2010 at 07:53 PM. Reason: Re-titled.
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Originally Posted by connroy17 Can somebody help me solve this equation? I have gotten to a certain point then get stuck. Thank you! 2/x^2-x = (1/x) + (4/x^2-1) Are the terms in the red part of exponent or not?
2/((x^2)-x) = (1/x) + (4/((x^2)-1) Hopefully that makes it easier to understand. The exponents are in red.
Move to one side and simplify: Obtain same common denominator. You can do that one.
Originally Posted by connroy17 2/((x^2)-x) = (1/x) + (4/((x^2)-1) Hopefully that makes it easier to understand. The exponents are in red. common denominator is ... note that x cannot equal 0 , 1 , or -1 (why?) with a common denominator, the numerators form the equation ... solve this quadratic for x
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