Can somebody help me solve this equation? I have gotten to a certain point then get stuck. Thank you!
2/x^2-x = (1/x) + (4/x^2-1)
$\displaystyle \frac{2}{x^2-x} = \frac{1}{x} + \frac{4}{x^2-1}
$
$\displaystyle \frac{2}{x(x-1)} = \frac{1}{x} + \frac{4}{(x+1)(x-1)}$
common denominator is $\displaystyle x(x+1)(x-1)$ ...
$\displaystyle \frac{2(x+1)}{x(x-1)(x+1)} = \frac{1(x+1)(x-1)}{x(x+1)(x-1)} + \frac{4x}{x(x+1)(x-1)}$
note that x cannot equal 0 , 1 , or -1 (why?)
with a common denominator, the numerators form the equation ...
$\displaystyle 2(x+1) = (x+1)(x-1) + 4x$
solve this quadratic for x