Consider the rational function f(x)= 3x^2 - 12 / x^2 - 3x + 2 A. Give the equation of the horizontal asymptote. B. Give the equation(s) of any vertical asymptotes. Thanks
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Is this right? f(x)= (3x^2 - 12) / (x^2 - 3x + 2) horizontal asymptote: y = 3 Vertical Asymptote: (x^2 - 3x + 2) = 0 (x - 2)(x - 1) = 0 x = 2 x = 1 Vertical Asymptotes: x = 1, x = 2
Originally Posted by rowdy3 Is this right? f(x)= (3x^2 - 12) / (x^2 - 3x + 2) horizontal asymptote: y = 3 Vertical Asymptote: (x^2 - 3x + 2) = 0 (x - 2)(x - 1) = 0 x = 2 x = 1 Vertical Asymptotes: x = 1, x = 2 Not quite, simplify the numerator too. Something will cancel out and you will have one less vertical asymptote. But you have the general idea behind this.
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