$\displaystyle \log_2 x + \log_4 x + \log_8 x = 11 $

Completely lost as to how to start this... only things Ive noticed so far are that bases of each log are all exponents of 2.

Would appreciate the help understanding this problem :P

Err srry... When x =2; the log base 4 of x is half that of log base 2 of x; and the log base 8 of x is a third of the log base 2 of x.. Had it backwards!