Let f be a function such that $\displaystyle f(n+1)=1-[f(n)]^2, \forall n\in\mathbb{Z}, n\geq0$. How would f(n+2) be expressed in terms of f(n)?
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Originally Posted by dwsmith Let f be a function such that $\displaystyle f(n+1)=1-[f(n)]^2, \forall n\in\mathbb{Z}, n\geq0$. How would f(n+2) be expressed in terms of f(n)? $\displaystyle f(n+1)=1-[f(n)]^2$ $\displaystyle \implies f(n+2) = f\left\{(n+1)+1\right\}=1-[f(n+1)]^2 = 1 - \left\{ 1-[f(n)]^2 \right\}^2$
Ok that trumps the ... answer first posed.
Originally Posted by dwsmith I am almost positive that isn't the answer but I could be wrong. Which step do you disagree with, particularly?
Originally Posted by Anonymous1 Which step do you disagree with, particularly? I don't disagree with that but when your response was first .... I was in disagreement.
Originally Posted by dwsmith I don't disagree with that but when your response was first .... I was in disagreement. Oh yeah that, haha. When I am fairly certain I know the answer, I like to secure my position. Cheers!
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