[SOLVED] function

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May 10th 2010, 05:27 PM
dwsmith

[SOLVED] function

Let f be a function such that $f(n+1)=1-[f(n)]^2, \forall n\in\mathbb{Z}, n\geq0$ . How would f(n+2) be expressed in terms of f(n)?
May 10th 2010, 05:30 PM
Anonymous1

Quote:

Originally Posted by dwsmith

Let f be a function such that $f(n+1)=1-[f(n)]^2, \forall n\in\mathbb{Z}, n\geq0$ . How would f(n+2) be expressed in terms of f(n)?

$f(n+1)=1-[f(n)]^2$

$\implies f(n+2) = f\left\{(n+1)+1\right\}=1-[f(n+1)]^2 = 1 - \left\{ 1-[f(n)]^2 \right\}^2$
May 10th 2010, 05:31 PM
dwsmith

Ok that trumps the ... answer first posed.
May 10th 2010, 05:37 PM
Anonymous1

Quote:

Originally Posted by dwsmith

I am almost positive that isn't the answer but I could be wrong.

Which step do you disagree with, particularly?
May 10th 2010, 05:38 PM
dwsmith

Quote:

Originally Posted by Anonymous1

Which step do you disagree with, particularly?

I don't disagree with that but when your response was first .... I was in disagreement.
May 10th 2010, 05:41 PM
Anonymous1

Quote:

Originally Posted by dwsmith

I don't disagree with that but when your response was first .... I was in disagreement.

Oh yeah that, haha.

When I am fairly certain I know the answer, I like to secure my position. (Evilgrin)

Cheers!

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