Hello,
Need help with solving the following log equation:
3Log(2x) = x-3
I have tried every possible method using log principles, but i am not getting the same answer as that when i use a GDC to look for the intersects. Please help.
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Hello,
Need help with solving the following log equation:
3Log(2x) = x-3
I have tried every possible method using log principles, but i am not getting the same answer as that when i use a GDC to look for the intersects. Please help.
Quote:
Originally Posted by BobBali
Code:>> syms x;
>> solve('3*log(2*x) = x-3',x)
ans =
1/(2*exp(1)*exp(lambertw(0, -1/(6*exp(1)))))
W = LAMBERTW(X) is the solution to w*exp(w) = x.
W = LAMBERTW(K,X) is the K-th branch of this multi-valued function.
(Crying) I was hoping a detailed step-by-step method was going to be shown. I want to know how we get the answer to 'x' ?
sorry you're disappointed, but the fact is that you'll not be able to solve this equation using elementary algebraic techniques.Quote:
Originally Posted by BobBali
the previous response shows a computer generated solution using the Lambert W function.
my advice to you is to get out your calculator and solve it.
graphand look for the real zero.
Sorry, I tried to do this at first...Quote:
Originally Posted by BobBali
Had to resort to MATLAB.
(Surprised) I cant solve this equation by hand..?! Oh, man... Yes, when i punched it originally into my GDC and looked for the intercept i got x = 6.3 , which checks out when i replace x in the equation. But, i was under the impression it could be solved by hand, apart from taking x/y values and plotting on a graph-paper by hand and looking for the intercepts... How did the Math-Gurus do it 30years ago?? They just graphed it by hand? (Surprised)