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Math Help - [SOLVED] Verifying Inverse of this Function

  1. #1
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    Cool [SOLVED] Verifying Inverse of this Function

    g(x)=\frac{2x-1}{x+3}

    My Attempt At The Inverse

    Let g(x)=z

    (x+3)(z)=2x-1

    xz+3z=2x-1

    1+3z=2x-xz

    1+3z=x(2-z)

    \frac{1+3z}{2-z}=x

    g^-1(x)=\frac{1+3x}{2-x}

    Where did I make a mistake?

    Thanks!
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  2. #2
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    Quote Originally Posted by unstopabl3 View Post
    g(x)=\frac{2x-1}{x+3}

    My Attempt At The Inverse

    Let g(x)=z

    (x+3)(z)=2x-1

    xz+3z=2x-1

    1+3z=2x-xz

    1+3z=x(2-z)

    \frac{1+3z}{2-z}=x

    g^-1(x)=\frac{1+3x}{2-x}

    Where did I make a mistake?

    Thanks!
    Why do you think there's a mistake. There is no mistake.
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  3. #3
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    Okay, great then!

    Thanks for the verification!
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