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Math Help - Find the limit by direct substitution.

  1. #1
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    Find the limit by direct substitution.

    Find the limit by direct substitution.

    A. lim x-> 5
    square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2.

    B. lim x-> -2
    (4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15. Here's a link to the problem. It's 3A and 3B. Thanks.
    http://pic20.picturetrail.com/VOL137.../386705398.jpg
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  2. #2
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    Quote Originally Posted by rowdy3 View Post
    Find the limit by direct substitution.

    A. lim x-> 5
    square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2.

    check your arithmetic ... the limit is -8

    B. lim x-> -2
    (4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15.

    correct
    ...
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  3. #3
    Member grgrsanjay's Avatar
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    Quote Originally Posted by rowdy3 View Post
    Find the limit by direct substitution.

    A. lim x-> 5
    square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2.

    B. lim x-> -2
    (4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15. Here's a link to the problem. It's 3A and 3B. Thanks.
    http://pic20.picturetrail.com/VOL137.../386705398.jpg
    check out this link its actually cube root of x^2-2x - 23
    its 3A question
    so actually it will be cube root of -8 = -2
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