# Find the limit by direct substitution.

• May 4th 2010, 07:13 PM
rowdy3
Find the limit by direct substitution.
Find the limit by direct substitution.

A. lim x-> 5
square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2.

B. lim x-> -2
(4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15. Here's a link to the problem. It's 3A and 3B. Thanks.
http://pic20.picturetrail.com/VOL137.../386705398.jpg
• May 5th 2010, 04:34 AM
skeeter
Quote:

Originally Posted by rowdy3
Find the limit by direct substitution.

A. lim x-> 5
square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2.

check your arithmetic ... the limit is -8

B. lim x-> -2
(4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15.

correct

...
• May 6th 2010, 07:08 AM
grgrsanjay
Quote:

Originally Posted by rowdy3
Find the limit by direct substitution.

A. lim x-> 5
square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2.

B. lim x-> -2
(4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15. Here's a link to the problem. It's 3A and 3B. Thanks.
http://pic20.picturetrail.com/VOL137.../386705398.jpg

check out this link its actually cube root of x^2-2x - 23
its 3A question
so actually it will be cube root of -8 = -2