# Thread: Logarithm Problem

1. ## Logarithm Problem

Can someone please help me solve:
log(3+x)-log(x-3)=log3

2. Originally Posted by Eshawnky
Can someone please help me solve:
log(3+x)-log(x-3)=log3
Are these logs all to the same base...?

3. Originally Posted by Eshawnky
Can someone please help me solve:
log(3+x)-log(x-3)=log3
Hi Eshawnky,

$\log(x+3)-\log(x-3)=\log 3$

Use this property: $\log a - \log b = \log \frac{a}{b}$

$\log \frac{x+3}{x-3}=\log 3$

$\frac{x+3}{x-3}=3$

$x+3=3(x-3)$

$x+3=3x-9$

$12=2x$

$x=6$

4. Thanks you're the best!

5. Originally Posted by masters
Hi Eshawnky,

$\log(x+3)-\log(x-3)=\log 3$

Use this property: $\log a - \log b = \log \frac{a}{b}$

$\log \frac{x+3}{x-3}=\log 3$

$\frac{x+3}{x-3}=3$

$x+3=3(x-3)$

$x+3=3x-9$

$12=2x$

$x=6$
wow an excellent and a simple way too,
i dint get this idea,
thanks