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Math Help - Logarithm Problem

  1. #1
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    Logarithm Problem

    Can someone please help me solve:
    log(3+x)-log(x-3)=log3
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  2. #2
    Junior Member piglet's Avatar
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    Quote Originally Posted by Eshawnky View Post
    Can someone please help me solve:
    log(3+x)-log(x-3)=log3
    Are these logs all to the same base...?
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  3. #3
    A riddle wrapped in an enigma
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    Quote Originally Posted by Eshawnky View Post
    Can someone please help me solve:
    log(3+x)-log(x-3)=log3
    Hi Eshawnky,

    \log(x+3)-\log(x-3)=\log 3

    Use this property: \log a - \log b = \log \frac{a}{b}

    \log \frac{x+3}{x-3}=\log 3

    \frac{x+3}{x-3}=3

    x+3=3(x-3)

    x+3=3x-9

    12=2x

    x=6
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  4. #4
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    Wink

    Thanks you're the best!
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  5. #5
    Member grgrsanjay's Avatar
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    Quote Originally Posted by masters View Post
    Hi Eshawnky,

    \log(x+3)-\log(x-3)=\log 3

    Use this property: \log a - \log b = \log \frac{a}{b}

    \log \frac{x+3}{x-3}=\log 3

    \frac{x+3}{x-3}=3

    x+3=3(x-3)

    x+3=3x-9

    12=2x

    x=6
    wow an excellent and a simple way too,
    i dint get this idea,
    thanks
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