f(x) = x(8-2x)(6x-2x)??
Question: Find the maximum y value of the graph between 0 ≤ x ≤ 3
f(x) = x(8-2x)(6-2x)
How would you find the maximum y value of this graph? Is it not like a parabola so when I tried finding the midpoint and then using the quadratic formula it didn't give me the highest value. Please explain the process and show your work. Thanks.
f(x) = x(8-2x)(6-2x) = 4x(4-x)(3-x) =
at the turning points
roots are and
until now all we know is these are turning points,
The value f ”(x) will tell us whether the point is a maximum or a minimum or a point of inflection
f''((7+sqr(13))/3) = positive, hence it is min
f''((7-sqr(13))/3) = negative, so this is max
f((7-sqr(13))/3) = 24.26