You can factor out 3^x
and have 0 for limit at
Therefore the limit is 1
Our teacher is being really nice (kinda) and teaching us some principles of calculus even if she shouldn't (crappy education system in my country), so you probably understand that we don't stay much at one principle in order to learn calculus.
The first was the limit, everything was OK until the teacher gave us an example that we didn't finish:
limit when x->inf. of function (4*2^x + 3^x)/(3*2^x + 3^x+1).
We always ended up to inf./inf. or 0/0, then she said (hope I translated right) we need to use base changing formulas and started to teach about slopes.
I couldn't find anything that could be under name "base change".
How could I solve this example? Does it have to do something with the mathematical constant e?
Thanks for your reply, that 3^x+1 is actually 3^(x+1), I made extra space to between numbers to see that, but now I see that this forum has mathtype, I will write it down with it:
P.S. maybe the teacher gave us a wrong example, like the same thing here? She didn't seem to check her notes, just started to solve it on her own.
wait a big, the script doesn't seem to understand this thing.
Ok I figured out how to write equations, but I used the source of your equation and added codes together.
It would be nice if someone told me the easy way