# Solve for x in the inequality

• May 1st 2010, 01:17 AM
VkL
Solve for x in the inequality
"Find x > 3 such that

ln(x) < x^(0.1)"

How do you do this?
• May 3rd 2010, 03:54 AM
CaptainBlack
Quote:

Originally Posted by VkL
"Find x > 3 such that

ln(x) < x^(0.1)"

How do you do this?

Numerically or graphically.

Use the bisection method to find a root of $f(x)=\ln(x)-x^{0.1}$ with starting points $a=3$, $b=3.5$

CB