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Math Help - integration again

  1. #1
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    integration again

    hmm can someone please check if this is correct for the next line:


     \int (e^x - 1)^6 e^x dx
    =
     \frac{x(x-1)^7 e^x }{7} + C

    ??
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  2. #2
    Super Member
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    Quote Originally Posted by Adre5 View Post
    hmm can someone please check if this is correct for the next line:


     \int (e^x - 1)^6 e^x dx
    =
     \frac{x(x-1)^7 e^x }{7} + C

    ??
    No. If you substitute e^x as t, the e^x*dx = dt.
    The integration becomes
    Int(t-1)^6*dt. And it is equal to
    (t-1)^7/7.
    Now substitute for t to get the final result.
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