# Math Help - integration again

1. ## integration again

hmm can someone please check if this is correct for the next line:

$\int (e^x - 1)^6 e^x dx$
=
$\frac{x(x-1)^7 e^x }{7} + C$

??

hmm can someone please check if this is correct for the next line:

$\int (e^x - 1)^6 e^x dx$
=
$\frac{x(x-1)^7 e^x }{7} + C$

??
No. If you substitute e^x as t, the e^x*dx = dt.
The integration becomes
Int(t-1)^6*dt. And it is equal to
(t-1)^7/7.
Now substitute for t to get the final result.