hmm can someone please check if this is correct for the next line:
$\displaystyle \int (e^x - 1)^6 e^x dx $
=
$\displaystyle \frac{x(x-1)^7 e^x }{7} + C $
??
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hmm can someone please check if this is correct for the next line:
$\displaystyle \int (e^x - 1)^6 e^x dx $
=
$\displaystyle \frac{x(x-1)^7 e^x }{7} + C $
??
No. If you substitute e^x as t, the e^x*dx = dt.Quote:
Originally Posted by Adre5
The integration becomes
Int(t-1)^6*dt. And it is equal to
(t-1)^7/7.
Now substitute for t to get the final result.
