Thread: Differentiation with trigonometry

Can someone please show me how this happens?

y = (1+sin^2 x)^3

y'= 3sin2x (1+sin^2 x)^2

because I thought that the differentiated form of sin^2x = 2sinxcosx

Originally Posted by CSG18

Can someone please show me how this happens?

y = (1+sin^2 x)^3

y'= 3sin2x (1+sin^2 x)^2

because I thought that the differentiated form of sin^2x = 2sinxcosx

Note that .

is equally correct.

Originally Posted by e^(i*pi)

Note that .

is equally correct.

Oh yes of course! Thank you very much, I can't believe I didn't spot that.