Can someone please show me how this happens? y = (1+sin^2 x)^3 y'= 3sin2x (1+sin^2 x)^2 because I thought that the differentiated form of sin^2x = 2sinxcosx
Follow Math Help Forum on Facebook and Google+
Originally Posted by CSG18 Can someone please show me how this happens? y = (1+sin^2 x)^3 y'= 3sin2x (1+sin^2 x)^2 because I thought that the differentiated form of sin^2x = 2sinxcosx Note that . is equally correct.
Originally Posted by e^(i*pi) Note that . is equally correct. Oh yes of course! Thank you very much, I can't believe I didn't spot that.
View Tag Cloud