Can someone please show me how this happens?

y = (1+sin^2 x)^3

y'= 3sin2x (1+sin^2 x)^2

because I thought that the differentiated form of sin^2x = 2sinxcosx

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- April 29th 2010, 03:02 PMCSG18Differentiation with trigonometry
Can someone please show me how this happens?

**y = (1+sin^2 x)^3**

y'= 3sin2x (1+sin^2 x)^2

because I thought that the differentiated form of sin^2x = 2sinxcosx - April 29th 2010, 03:08 PMe^(i*pi)
- April 29th 2010, 03:15 PMCSG18