Hi, I've already proven that dy/dx=1/2{1-(9/[2t^2+1])} How do I show that dy/dx<1/2?? Thanks a lot!
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Originally Posted by cyt91 Hi, I've already proven that dy/dx=1/2{1-(9/[2t^2+1])} How do I show that dy/dx<1/2?? Thanks a lot! Hi cyt91, and as the numerator of the second factor is clearly less than the denominator, the second factor is less than one, hence the overall expression is less than 0.5
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