Is it because it is against the rules to added a line at the end of the magnitude of 6000 which forms a 90 degree angle? Should I solve for the vector component of each line first?
Tow Line Tension- A loaded barge is being towed by two tugboats, and the magnitude of the resultant is 6000 pounds directed along the axis of the barge. Find the tension in the tow lines if they each make an 18 degree angle with the axis of the barge.
I don't understand why I cant just use law of sin to solve for the magnitude of the tow line. My understanding, which probably is flawed somewhere that I don't see, is thinking why does it not compute correctly if I find the third angle to be 72 degrees if 180-32-90=third angle. So sin(72)/6000=sin(90)/tow line.
I get 6308.8 but the answer in the book is 3154.4. Im stumped about how to do this problem