Please help me with a). I do not understand how to find the formula from the lines.
for g(x), your function will be:
$\displaystyle y-(-1) = \frac{0-(-1)}{3-0} (x-0)$
$\displaystyle y+1 = \frac{1}{3} x$
$\displaystyle y = \frac{x}{3} -1$
$\displaystyle \therefore g(x) = \frac{x}{3} -1 = \frac{x-3}{3}$
As instructed before, do the same for f(x).
Remember that you are using two-point form to find the equation(s) of the line(s).
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Thank you so much for your continual help. I got the same answer using the
y = mx + b method.
Anyways should there be a limit on what x values these formulas should operate in? Because if there wasn't any, the lines will proceed to go further than the point of intersection between f(x) and g(x).