Find such that
I thought i was doing fine until i ran into this problem:
x^2+4x-8/x^3-x^2-4x+4
soooo.... i factored out the bottom and got
x^2+4x-8/(x+2)(x-2)(x-1)
I have never encountered a problem like this one...
Can any one help me out?
Thank you, SO much.
NO!!
Look at what pickslides and soroban have suggested.
You should definitely have these kind of examples in you book/notes. Otherwise Google is there.
You can decompose the given term as:
So,
.....(I)
you have to use equation (I) to find the values of A,B,and C
first,
let x=1, then equation (I) becomes:
this gives:
Now set x = 2 and C=1 in equation (I) , and you'll find the value of B.
Lastly, set x = -2, and you'll find the value of A.
Thus you have the values of A,B and C and your partial fraction is decomposed.
Thank you all very much,
Sorry for appearing as a moron.
But i had explained my situation before
Our this a math 40 course, and our professor gives us take home "exams" with material from math 101-140 (sometime a lil higher) and this is what he grades us on. He actually straight up tells us that none of this stuff is in our books, but that he wants to weed out the weak ones....
srsly, i think this guy is ****ing nuts, many complains have been filled on him, but no one seems to care......
once again thank you all very much for helping me (and a few other of my classmates out with this stuff)