Thread: Q in Inverse Tangent Funquen

1. Q in Inverse Tangent Funquen

Hi

here in like thi9s queation we use ( Rad ) or (deg ) in the calcolator ?

2. Originally Posted by r-soy
Hi

here in like thi9s queation we use ( Rad ) or (deg ) in the calcolator ?

Consider the angle $\theta = \arccos\left(\frac{-\sqrt{3}}{2}\right)$

Look at the $30-60-90$ triangle here Special right triangles - Wikipedia, the free encyclopedia

Do you notice anything about the side lengths in relation to the problem?

Now map this onto this circle for where $\cos$ is negative. Have a read of this. http://www.haverford.edu/physics/Mat...Trig_Ident.pdf