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Math Help - QUEATION IN POLAR I am amazed by these solutions

  1. #1
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    QUEATION IN POLAR I am amazed by these solutions

    hI

    QUEATION IN POLAR I am amazed by these solutions

    we now Q in one or third or fourth guadrant are diffrence

    but here in this 2 quetion the solving are differnt when find Q Although the point in fourth guadrant in both quetion

    See solving one why say - pi - 60
    and anthoer 2 p- - 45

    Although the point in fourth guadrant ??

    see these soitions

    please help me
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  2. #2
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    Whenever cosθ is positive and sinθ is negative, θ is always in the fourth quadrant.
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  3. #3
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    By the way, when you write " 2\pi- 60" and " 2\pi- 45 you are mixing "radians" and "degrees". Never do that!

    In fact, except in problems specifically involving angles measured in degrees, you should always use radians.

    Your answers should be \sqrt{2}e^{(2\pi- \pi/4)i}= \sqrt{2}e^{7i\pi/4} and 2e^{(2\pi- 2\pi/3)i}= 2e^{4i\pi/3}.

    Of course, since e^x has period 2i\pi, you could more easily just write \sqrt{2}e^{-i\pi/4} and 2e^{-2i\pi/3}.
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  4. #4
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    thanks but my question now why the answer in one - pi - 60
    and anthoer 2 p- - 45 the point in foruth guadrant an As we know Angle in foruth guadrant = - pi - Q
    why they use 2pi - Q ??????? this id my question
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  5. #5
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    Quote Originally Posted by r-soy View Post
    thanks but my question now why the answer in one - pi - 60
    and anthoer 2 p- - 45 the point in foruth guadrant an As we know Angle in foruth guadrant = - pi - Q
    why they use 2pi - Q ??????? this id my question
    In the polar co-ordinates, the angle of rotation of the radius vector is measured in counter clockwise direction.
    So the angle in the fourth quadrants is (2π - θ) or (3π/2 + θ)
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