Hello, a little stuck on a question: Integrate (x+1)(x+3)^5 u = (x+3) I have ended up with 1/7(x+3)^7 - 1/3(x+3)^6 + K but the answer is 1/21 (x+3)^6(3x+2) ... Can someone show me how to do it please Thanks!
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You integrate the thing and then you will get From your answer take (x+3)^6 out as common factor You will get (x+3)^6 [ 1/7(x+3) - 1/3] + K Any more help ?
i must have made a mistake somewhere else because although thats very useful and what i was missing (thank you ) the answer i now get is: 21(x+3)^6(3x+2) whereas the answer is: ... ??
Last edited by darksupernova; Apr 20th 2010 at 03:37 AM.
Originally Posted by darksupernova i must have made a mistake somewhere else because although thats very useful and what i was missing (thank you ) the answer i now get is: 21(x+3)^6(3x+2) whereas the answer is: 1/21 (x+3)^6(3x+2) ... ?? That's it! Feel free to ask if you still find it difficult ..
ahh... didnt think about doing that!! thanks!
Originally Posted by darksupernova Hello, a little stuck on a question: Integrate (x+1)(x+3)^5 u = (x+3) I have ended up with 1/7(x+3)^7 - 1/3(x+3)^6 + K but the answer is 1/21 (x+3)^6(3x+2) ... Can someone show me how to do it please Thanks! Hi darksupernova, Using your substitution u=x+3, so x+1=u-2, du=dx
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