f(x)=2x, where x is any real no.
g(x)=|cos x|-cos x where 0<=x<=2 pi.
Does composite function gf exists?
From the domain of f,doesn't the range of f lies outside the domain of g? If it exists,why is it so and what's the domain of gf???
Thanks a lot! (Bow)
The function gf will have domain equal to the set of all x in the domain of f such that f(x) is in the domain of g. Since the domain of g is given as "0<= x<= 2pi", and f just doubles x, the domain of gf is "0<= x<= pi".
Originally Posted by cyt91