My attempt at manipulating the equation
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Originally Posted by Punch My attempt at manipulating the equation hi your equation is correct . gradient -- equation 1 the y-intercept is 2 , so we know another point (0,2) gradient -- equation 2 so now you hv 2 equations , whats next ?
You are right Using the point (4,-4) gives you the value for a Then using the point (2,b) gives you the value for b
From , substituting the point (4,-4) I would have to take which shows error 2 in the calculator. confused
Originally Posted by Punch From , substituting the point (4,-4) I would have to take which shows error 2 in the calculator. confused ln y (the whole thing) is -4 not the y inside the ln .
Oh... This means, is expressed as Y=mX+C where where Y is the y coordinate and X is the x-coordinate
Originally Posted by Punch Oh... This means, is expressed as Y=mX+C where where Y is the y coordinate and X is the x-coordinate yes
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