Hi again all,

I am asked to find domain and range of an f(x) and the range of its inverse f^-1(x):

f(x) = sqrt(2x - 5)

So I found the domain of this to be x >or= 5/2. I'm not too good at getting range so I decided to find the domain of the inverse which would then be the range of the original. My inverse turned out to be:

f^-1(x) = (x^2 + 5)/ 2

So then it seems like the domain to the above inverse function would be all real numbers, but then I had trouble verifying that the range of my original was all real numbers cause how could the range of f(x) = sqrt(2x - 5) be a negative number?