Solve each for the stadard form:

(x - h)^2 = 4p(y - k) <-- vertical parabola

(y - k)^2 = 4p(x - h) <-- horizontal parabola

x^2 + 4x + 6y - 2 = 0

(x^2 + 4x + 4) = -6y + 2 + 4 = -6y + 6

(x + 2)^2 = -6(y - 1) <-- vertical parabola

The focal length is: 4p = -6 --> p = -3/2 <-- this is the distance from the vertex to the directrix line and to the focus. Since this parabola is VERTICAL, the focus and directrix are ABOVE and BELOW the vertex.

The vertex is: (h,k) = (-2,1)

The focus is "p" units above the vertex: (-2,1 + p) = (-2,1 - 3/2) = (-2,-1/2)

The directrix is "p" units below the vertex: y = 1 - p = 1 - (-3/2) = 5/2