Hi, I need help with these. Simplfy as much as possible.
((3x2^n+1) + (5x2^n)) / ((7x2^n) - (3x2^n-1))
solve for x
2y-1/1-x = 2y+1 x not =1 , y not =-1/2
solve for s
2s - 2/s = 3 s not = 0
Wrong form but here is what you are looking for if this is the equation you mean
$\displaystyle \frac{3x2^{n+1}+5x2^n}{7x2^n-3x2^{n-1}}$
Factor out a $\displaystyle x$ and $\displaystyle 2^n$
$\displaystyle \frac{x2^n(3*2+5)}{x2^n(7-\frac{3}{2})}=\frac{11}{\frac{11}{2}}=2$
Obtain the same common denominator
$\displaystyle \frac{2s^2-2}{s}=3\Rightarrow\frac{2(s^2-1)}{s}=3\Rightarrow\frac{s^2-1}{s}=\frac{3}{2}\Rightarrow s^2-1=\frac{3s}{2}\Rightarrow s^2-\frac{3s}{2}-1$$\displaystyle =\frac{1}{2}(s-2)(2s+1)\Rightarrow s=2$ and $\displaystyle s=\frac{-1}{2}$