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Math Help - Solving equations.

  1. #1
    Junior Member
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    Solving equations.

    Hi, I need help with these. Simplfy as much as possible.

    ((3x
    2^n+1) + (5x2^n)) / ((7x2^n) - (3x2^n-1))


    solve for x

    2y-1/1-x = 2y+1 x not =1 , y not =-1/2


    solve for s

    2s - 2/s = 3 s not = 0

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  2. #2
    Junior Member
    Joined
    Jun 2008
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    Quote Originally Posted by tim_mannire View Post
    Hi, I need help with these. Simplfy as much as possible.



    ((3x2^n+1) + (5x2^n)) / ((7x2^n) - (3x2^n-1))


    solve for x

    2y-1/1-x = 2y+1 x not =1 , y not =-1/2


    solve for s

    2s - 2/s = 3 s not = 0

    ((3x is apart of the equation below.. i dont know y it isolated itself like that!
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  3. #3
    MHF Contributor
    Joined
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    Thanks
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    Wrong form but here is what you are looking for if this is the equation you mean

    \frac{3x2^{n+1}+5x2^n}{7x2^n-3x2^{n-1}}

    Factor out a x and 2^n

    \frac{x2^n(3*2+5)}{x2^n(7-\frac{3}{2})}=\frac{11}{\frac{11}{2}}=2

    Obtain the same common denominator

    \frac{2s^2-2}{s}=3\Rightarrow\frac{2(s^2-1)}{s}=3\Rightarrow\frac{s^2-1}{s}=\frac{3}{2}\Rightarrow s^2-1=\frac{3s}{2}\Rightarrow s^2-\frac{3s}{2}-1 =\frac{1}{2}(s-2)(2s+1)\Rightarrow s=2 and s=\frac{-1}{2}
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