find sin (theta).
tan(theta)= - (sqrt)7/2
sec(theta)>0
I'm sorry if this is confusing to you all(math editor) I am also very confused! Please help!
Dear momuvfour,
It is given that $\displaystyle sec\theta>0\Rightarrow{cos\theta<0}$That is theta is in the second or third quadrants. Hence we have to find values for $\displaystyle tan\theta=-\frac{\sqrt{7}}{2}$ such that theta will be in the second or third quadrants. Can you continue from here??
Dear macosxnerd101,
By taking $\displaystyle \theta=arctan\left(-\frac{\sqrt{7}}{2}\right)$ you have only considered the case where theta is in the second quadrant.
Hope this will help you.