Can someone please show me the steps needed to achieve the answers to this question?
A helicopter holding a 70kg package suspended from a 5m long rope accelerates upward at 5.2m/s^2. When the velocity of the helicopter is 30m/s up, the rope is cut. The helicopter continues to accelerate at 5.2m/s^2 up. find the distance between the helicopter and the package 2 seconds after the rope is cut.
I know that's going to be a lot of work, but any help is much appreciated. =)
Helicopter: Iinitial velcocity = 30 m/s, acceleration = 5.2 m/s^2, t = 2 s, Displacement = x2 = ?
Distance between parcel and helicopter = x2 + 5 - x1 (the 5 comes from the rope)