I'm in pre-calculus and I'm completely clueless with these 2 problems.
1) The radioactive isotope of carbon-14c has a half life of 5730 years.
A) What is the decay constant of carbon-14c
B) If we start with a sample of 1000 carbon14 nuclei, how many will be left in 22,290 years time.
2) A Piece of charcoal of mass 25g is found in the ruins of an ancient city. The sample shows a carbon-14 activity or R(t)= 4.167 decays/second.
A) Convert the decay constant of carbon-14c from (1)(a) in terms of seconds instead of years.
B) Find the number f remaining atoms of N(t) using the constant you found in (a)
C) Suppose that the initial number of carbon-14c nuclei before decay is 1.63x10^12. What was the initial rate of decay ( or R initial)
D) How long has the tree that this charcoal came from been dead?
Okay so I'm given these equations
Originally Posted by farhadfarzadsucks
So the equation for part 1, Since you know that your initial amount is 1/2 at time t=5730, you can assume values for your initial and final values
i'll use 10 and 20 as an example
Then use properties of logs to solve for c and this will be the decay rate
Part 2, use that decay rate to determine the amount left after t=22,290
Uhm, I haven't learned that method or not used to doing that.
Originally Posted by xsavethesporksx
Or do I just plug in the numbers?