# Thread: Finding the first five terms of a sequence.

1. ## Finding the first five terms of a sequence.

What are the first 5 terms of the sequence:
an = (2^n / n!)

Any help is appreciated

2. Originally Posted by iluvmathbutitshard
What are the first 5 terms of the sequence:
an = (2^n / n!)

Any help is appreciated
$A_n = \frac{2^n}{n!}$

Let $n = {1,2,3,4,5}$ and these are your terms.

3. Do you understand that this is simply arithmetic and doing what you are told ?

If, as you say, $a_n= 2^n/n!$ then $a_0= 2^0/0!= 1/1= 1$. $a_1= 2^1/1!= 2/1= 2$. $a_1= 2^2/2!= 4/2= 2$. $a_3= 2^3/3!= 8/6= 4/3$. $a_4= 2^4/4!= 16/24= 2/3$.

4. I actually already solved the problem and got the correct answer.