What are the first 5 terms of the sequence:
an = (2^n / n!)
Any help is appreciated
Do you understand that this is simply arithmetic and doing what you are told ?
If, as you say, $\displaystyle a_n= 2^n/n!$ then $\displaystyle a_0= 2^0/0!= 1/1= 1$. $\displaystyle a_1= 2^1/1!= 2/1= 2$. $\displaystyle a_1= 2^2/2!= 4/2= 2$. $\displaystyle a_3= 2^3/3!= 8/6= 4/3$. $\displaystyle a_4= 2^4/4!= 16/24= 2/3$.