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About LinkBacksHow would I find these zeros?I tried factoring by grouping but it doesnt give me the correct answer:
y=-4x^3+12x^2+96x+112
The first term is negative
Originally Posted by nascar77
How would I find these zeros?
y=-4x^3+12x^2+96x+112
The first term is negative
using the rational root theorem,is a zero for
... you should be able to find the two other zeros with that piece of information.
#1 - Simplify your life. Same solutions as this: 0 = x^3 - 3x^2 - 24x - 28
#2 - Rule of Signs: One Positive Real. Two or Zero Negative
#3 - Rational Roots: +/-1, +/-2, +/-4, +/-7, +/-14, +/-28
--------- 7 Works
#4 - Reduction: (x^3 - 3x^2 - 24x - 28)/(x - 7) = (x^2 + 4x + 4)
#5 - That is easily factored.
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