How would I find these zeros? (Worried) I tried factoring by grouping but it doesnt give me the correct answer:

y=-4x^3+12x^2+96x+112

The first term is negative

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- Apr 4th 2010, 04:00 PMnascar77How to find the zeros of an equation?
How would I find these zeros? (Worried) I tried factoring by grouping but it doesnt give me the correct answer:

y=-4x^3+12x^2+96x+112

The first term is negative - Apr 4th 2010, 04:10 PMskeeter
- Apr 4th 2010, 04:15 PMTKHunny
#1 - Simplify your life. Same solutions as this: 0 = x^3 - 3x^2 - 24x - 28

#2 - Rule of Signs: One Positive Real. Two or Zero Negative

#3 - Rational Roots: +/-1, +/-2, +/-4, +/-7, +/-14, +/-28

--------- 7 Works

#4 - Reduction: (x^3 - 3x^2 - 24x - 28)/(x - 7) = (x^2 + 4x + 4)

#5 - That is easily factored.