Results 1 to 6 of 6

Math Help - Graphing Parabola

  1. #1
    Junior Member
    Joined
    Mar 2010
    Posts
    27

    [Solved] Graphing Parabola

    x=-5(y+4)^2+3

    How do I start

    Thanks
    Last edited by ToXic01; March 29th 2010 at 10:18 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    Quote Originally Posted by ToXic01 View Post
    x=-5(y+4)^2+3

    How do I start

    Thanks
    Hi ToXic01,

    Well, first note that the equation is in vertex form:

    x=a(y-k)^2+h

    This allows you to find the vertex rather quickly.

    V(h, k)

    Since a < 0, the parabola opens to the left.

    The axis of symmetry is y = k.

    Now, if you want specific points to graph, assign some arbitrary values to y and solve for x.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    Mar 2010
    Posts
    27
    how about focus, directrix,
    Follow Math Help Forum on Facebook and Google+

  4. #4
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    Quote Originally Posted by ToXic01 View Post
    how about focus, directrix,
    You'll find the focus at \left(h+\frac{1}{4a}, k\right)

    and the directrix at  x=h-\frac{1}{4a}
    Follow Math Help Forum on Facebook and Google+

  5. #5
    A riddle wrapped in an enigma
    masters's Avatar
    Joined
    Jan 2008
    From
    Big Stone Gap, Virginia
    Posts
    2,551
    Thanks
    12
    Awards
    1
    You're welcome.


    Follow Math Help Forum on Facebook and Google+

  6. #6
    Junior Member
    Joined
    Mar 2010
    Posts
    27
    Thanks
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. graphing this parabola
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: August 17th 2010, 07:20 AM
  2. Replies: 1
    Last Post: May 21st 2010, 11:44 PM
  3. Replies: 1
    Last Post: March 4th 2010, 04:01 PM
  4. Confusion! Graphing a Parabola in Standard Form
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: September 15th 2009, 12:42 PM
  5. Graphing Parabola
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: December 4th 2008, 03:18 AM

Search Tags


/mathhelpforum @mathhelpforum