Derive the indicated result by appealing to the geometric series |x| < 1 |x| < 1 I dun understand what the question is asking, the geometric series is 1/(1-x), how does it turn into 1/(1+x)
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Originally Posted by wopashui Derive the indicated result by appealing to the geometric series |x| < 1 |x| < 1 I dun understand what the question is asking, the geometric series is 1/(1-x), how does it turn into 1/(1+x) You should know that for . In your first question and in your second question .
Originally Posted by wopashui I dun understand what the question is asking, the geometric series is 1/(1-x), how does it turn into 1/(1+x) Simple. Just replace x by –x.
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