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Math Help - need help solving for x

  1. #1
    Junior Member surffan's Avatar
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    need help solving for x

    i have a couple questions where im stuck at the part where i have to solve for x. these are the equations in which i need to solve for x

    15x/(x^2 +14400)^(1/2) -10 = 0

    and
    4c(2x^2)+c(2x^2)+c(2880/x)+c(1440/x)
    where i need to first solve for the derivative and then solve for x
    Last edited by surffan; March 28th 2010 at 05:39 PM. Reason: typo
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  2. #2
    Master Of Puppets
    pickslides's Avatar
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    Quote Originally Posted by surffan View Post
    i have a couple questions where im stuck at the part where i have to solve for x. these are the equations in which i need to solve for x

    15x/(x^2 +14400)^(1/2) -10 = 0

    and
    4c(2x^2)+c(2x^2)+c(288/x)+c(1440/x)
    where i need to first solve for the derivative and then solve for x

    Is this your function?

     \frac{15x}{(x^2 +14400)^{\frac{1}{2}} }-10 = 0
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  3. #3
    Junior Member surffan's Avatar
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    yes
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  4. #4
    Master Of Puppets
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     \frac{15x}{(x^2 +14400)^{\frac{1}{2}} }-10 = 0

     \frac{15x}{(x^2 +14400)^{\frac{1}{2}} } = 10

     \frac{15x}{\sqrt{x^2 +14400} } = 10

     15x = 10\sqrt{x^2 +14400}

    Squaring both sides

     225x^2 = 100(x^2 +14400)

    Now expand right hand side, group like terms and solve.
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