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Math Help - Limits

  1. #1
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    Limits

    Use the epsilon-delta definition of limit to prove \lim_{x\to -1}\frac{x^2-3}{x+2}=-2
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  2. #2
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    \left|\frac{x^2- 3}{x+ 2}- (-2)\right|= \left|\frac{x^2+ 2x+ 1}{x+2}\right| =\left|\frac{(x+ 1)^2}{x+2}\right|.

    Does that help?
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  3. #3
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    not really, thats where i got stuck. i dunno if this is rite but...

    |x+1|<\frac{1}{2}\Rightarrow \frac{1}{2}<x+2<\frac{3}{2}
    \frac{|x+1|^2}{|x+2|}<2|x+1|^2

    and then set delta=sqrt(epsilon/2)
    Last edited by vuze88; March 28th 2010 at 09:47 PM.
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