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Math Help - Turning point of the curve

  1. #1
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    Turning point of the curve

    The curve y=hx^2+\frac{k}{x} has a turning point at P(\frac{1}{2},6).Find

    (i)the value of h and k

    (ii)the equation of tangent to the curve at x=1
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  2. #2
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    Quote Originally Posted by mastermin346 View Post
    The curve y=hx^2+\frac{k}{x} has a turning point at P(\frac{1}{2},6).Find

    (i)the value of h and k

    (ii)the equation of tangent to the curve at x=1
    the point P\left(\frac{1}{2} , 6 \right) is on the curve ...

    6 = \frac{h}{4} + 2k


    since P is a turning point ...

    y'\left(\frac{1}{2}\right) = 0

    use the above equation to get a second equation in terms of h and k ... then solve the system of equations.
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    still dont understand..please help
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  4. #4
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    Quote Originally Posted by mastermin346 View Post
    still dont understand..please help
    show me the derivative of y , then I'll provide more direction.
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