Results 1 to 4 of 4

Math Help - log problem

  1. #1
    Member
    Joined
    Oct 2009
    Posts
    202

    log problem

    solve the following equation

    \log_{\sqrt x}16-\log_{\sqrt x}2=3
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,894
    Thanks
    691
    Quote Originally Posted by mastermin346 View Post
    solve the following equation

    \log_{\sqrt x}16-\log_{\sqrt x}2=3
    use this property of logarithms on the left side of the equation ...

    \log_a{m} - \log_a{n} = \log_a\left(\frac{m}{n}\right)<br />

    ... then convert the resulting log equation to an exponential equation and solve for x.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2010
    Posts
    3
    \log_{\sqrt{x}}8 = 3

    \sqrt{x} ^ {log_{\sqrt{x}}8} = \sqrt{x} ^ 3

    8 = x ^ \frac{3}{2}

    x = 8 ^ \frac{3}{2}

    x = 4
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,894
    Thanks
    691
    Quote Originally Posted by Subcydian View Post
    \log_{\sqrt{x}}8 = 3

    \sqrt{x} ^ {log_{\sqrt{x}}8} = \sqrt{x} ^ 3

    8 = x ^ \frac{3}{2}

    x = 8 ^ \frac{3}{2}

    \textcolor{red}{x = 8^{\frac{2}{3}}}

    x = 4
    ...
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum