The coordinates ofand
of an equilateral are
and
respectively.
is perpendicular to
whereas the straight line
is parallel to
.Find
a)the equation of straight line
b)the coordinates of point
c)the equation of locussuch that the distance of
and
are equal.
Since EG is perpendicular to FH, which has slope 1/2, EG has slope -2. That means that EG has equation y= -2(x- 3)+ 3.Originally Posted by lindros
The coordinates of
a)the equation of straight line
Since FG is parallel to the x-axis, G must have the same y coordinate as F: -1. Solve -1= -2(x- 3)+ 3 to find the x coordinate.b)the coordinates of point
This is the straight line perpendicular to EF and passing through its midpoint. EF has slope (3-(-1))/(3- 0)= 4/3 so this line has slope -3/4. The midpoint of EF is ((3+(-1))/2, (3+ 0)/2).c)the equation of locus
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